Calculate the oxidation number of Nitrogen in **NH _{4}NO_{3}**.

Let us consider the oxidation of nitrogen to be x

also we know that the oxidation state of hydrogen is +1 and the oxidation state of **NO ^{3-}** is

**-1**.

Now,

x + (+1) × 4 + (-1) = 0

x + 4 = 0

x = -3

**Hence , the oxidation number of nitrogen is -3.**