Here,

mass of CO_{2} = 5kg = 5 × 1000 = 5000 g

Also we know that

At STP ,

44 g of CO_{2} will produce 22.4 L of CO_{2} gas.

5000g of CO_{2} will produce (22.4 × 5000 ) / 44 L of CO_{2} gas

** = 2545.45 L**

The volume of CO_{2 }that will come out is 2545.45 – 10 = **2535.45 L**

**Hence, the volume of CO _{2} gas delivered is 2545.45 L.**