Q.1. 16 g of a gas at STP occupies 5.6 L. What is the molecular mass of the gas ?
We know that
5.6 L of a gas weight 16 g at STP.
22.4 L of a gas weights = ( 16 * 22.4) / 5.6 g at STP = 64 g.
Q. 2. What volume would 5.5 g CO2 occupy at STP?
44 g of CO2 gas will occupy 22.4 L
5.5 g of CO2 gas will occupy = ( 22.4 * 5.5 ) / 44 = 2.8 L = 2800 L
Q.3. Calculate the volume of 11 g of CO2 at NTP?
44 g of CO2 will occupy 22400 mL.
11 g of CO2 will occupy = (22400 * 11) / 44 = 5600 mL.
Q.4. Calculate the weight , in g of 5.6 L of Chlorine gas at STP.
22.4 L of Cl2 gas weight 71 g
5.6 L of Cl2 gas weight = ( 71 * 5.6 ) / 22.4 = 17.75 g.